Aspire Faculty ID #15118 · Topic: JAMIA MILLIA ISLAMIA MCA 2018 · Just now
JAMIA MILLIA ISLAMIA MCA 2018

Find the remainder when $67^{99}$ is divided by 7.

Solution

$67 \equiv 4 \pmod7$, so $4^3 \equiv 1$. $99$ is multiple of 3 → remainder $=1$.
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