Aspire Faculty ID #15398 · Topic: MAH MCA CET 2023 · Just now
MAH MCA CET 2023

In the triangle $ABC$, sides $AB$, $BC$, and $CA$ are extended such that $B'$, $C'$, and $A'$ are the new points formed. If the area of $\triangle ABC = 1$ unit and $AA' = 2AB,\ BB' = 2BC,\ CC' = 3AC$, then find the area of $\triangle A'B'C'$.

Solution

Each side is scaled by 2, 2, and 3 respectively; the area ratio depends on the product of scale factors. Hence, area $= 18$ times original.

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