Aspire Faculty ID #15942 · Topic: JEE Main 2018 (Offline) · Just now
JEE Main 2018 (Offline)

Let $a_1, a_2, a_3, \ldots, a_{49}$ be in A.P. such that $\displaystyle \sum_{k=0}^{12} a_{4k+1} = 416$ and $a_9 + a_{43} = 66$. If $a_1^{2} + a_2^{2} + \cdots + a_{17}^{2} = 140m$, then $m$ is equal to :

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