Aspire Faculty ID #16797 · Topic: AMU MCA 2025 · Just now
AMU MCA 2025

A discrete random variable follows Poisson distribution with parameter $3$. The value of $E(X-6)^2$ is:

Solution

For Poisson distribution, Mean $= \lambda = 3$ Variance $= \lambda = 3$ $E(X-6)^2 = \text{Var}(X) + (E(X) - 6)^2$ $= 3 + (3 - 6)^2 = 3 + 9 = 12$
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