Aspire Faculty ID #16801 · Topic: AMU MCA 2025 · Just now
AMU MCA 2025

A discrete random variable $X$ taking non-negative values has the following moment generating function $M_X(t) = e^{2(e^t-1)},; -\infty < t < \infty$ Then, the value of $P(X \le 1)$ is:

Solution

Given MGF corresponds to Poisson distribution with $\lambda = 2$. $P(X \le 1) = P(0)+P(1)$ $= e^{-2} + 2e^{-2} = 3e^{-2}$

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