Aspire Faculty ID #16808 · Topic: AMU MCA 2025 · Just now
AMU MCA 2025

Let $T:\mathbb{R}^4 \rightarrow \mathbb{R}^3$ be a linear transformation defined by $T(x_1,x_2,x_3,x_4)=C(x_1-x_2,;x_2-x_3,;x_3-x_4)$ Then which of the following is true?(i) $\dim(\ker T)=1$ if $C \ne 0$ (ii) $\dim(\ker T)=0$ if $C=0$ (iii) $\dim(\ker T)=1$ if $T$ is onto

Solution

For $C \ne 0$, kernel has dimension 1. If $T$ is onto, rank is 3, hence nullity is 1.

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