Aspire Faculty ID #17089 · Topic: AMU MCA 2021 · Just now
AMU MCA 2021

The greatest value of $f(x,y)=xy$ on ellipse $ \frac{x^2}{8}+\frac{y^2}{2}=1 $

Solution

Using Lagrange multipliers, maximum occurs at $ x=2,\ y=1 $ So $ xy=2 $

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