Aspire Faculty ID #17890 · Topic: JEE Main 2026 (21 January Morning Shift) · Just now
JEE Main 2026 (21 January Morning Shift)

Let $a_1, a_2, a_3, \ldots$ be a G.P. of increasing positive terms such that $a_1 a_2 a_3 a_4 = 64$ and $a_1 + a_2 + a_3 = \frac{813}{7}$. Then $a_3 + a_5 + a_7$ is equal to:

Solution

$ar \cdot ar^2 \cdot ar^3 = 64$


$a^3 r^6 = 64 \Rightarrow ar^2 = 4$


$a + ar + ar^2 = \frac{813}{7}$


$r^2 = 28$


$ar^2 + ar^4 + ar^6 = 4(1 + r^2 + r^4) = 4(1 + 28 + 784) = 3252$

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