Aspire Faculty ID #18046 · Topic: JEE Main 2026 (24 January Morning Shift) · Just now
JEE Main 2026 (24 January Morning Shift)

Let $f(t)=\int \frac{1-\sin(\log_e t)}{1-\cos(\log_e t)}dt,; t>1$ If $f(e^{\pi/2})=-e^{-\pi/2}$ and $f(e^{\pi/4})=\alpha e^{-\pi/4}$, then $\alpha$ equals:

Solution

Put $\ln t=x$

$f(t)=\int \frac{1-\sin x}{1-\cos x}e^x dx$

$=\frac{1}{2}\int (\csc^2\frac{x}{2}-2\cot\frac{x}{2})e^x dx$

Using standard form

$f(x)=e^x\cot\frac{x}{2}+C$

Using given values ⇒ $C=0$

$f(e^{\pi/4})=-e^{-\pi/4}(\sqrt{2}+1)$

$\Rightarrow \alpha=-1-\sqrt{2}$

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