Aspire Faculty ID #18048 · Topic: JEE Main 2026 (24 January Morning Shift) · Just now
JEE Main 2026 (24 January Morning Shift)

Let $A(1,0),; B(2,-1)$ and $C\left(\frac{7}{3},\frac{4}{3}\right)$ be three points. If equation of bisector of angle $ABC$ is $\alpha x+\beta y=5$, then $\alpha^2+\beta^2$ is:

Solution


Using internal angle bisector

Slope $=-3$

Equation ⇒ $\alpha=3,; \beta=1$

$\alpha^2+\beta^2=10$

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