Aspire Faculty ID #18307 · Topic: AMU MCA 2017 · Just now
AMU MCA 2017

If the sum of $n$ terms of an AP is $S_n=nR+\frac{1}{2}n(n-1)T$, where $R$ and $T$ are constants, then the common difference is

Solution

$ S_n=nR+\frac{1}{2}n(n-1)T $ $ S_1=R $ $ S_2=2R+\frac{1}{2}\cdot2\cdot1\cdot T=2R+T $ $ \Rightarrow a_1=R,\ a_2=R+T $ $ \Rightarrow d=a_2-a_1=(R+T)-R=T $

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