Aspire Faculty ID #18340 · Topic: AMU MCA 2017 · Just now
AMU MCA 2017

If $A=\begin{bmatrix}\alpha & 0 \\ 1 & 1\end{bmatrix}$ and $B=\begin{bmatrix}1 & 0 \\ 5 & 1\end{bmatrix}$ and $A^2=B$, then the value of $\alpha$ is

Solution

$A^2 = \begin{bmatrix}\alpha & 0 \\ 1 & 1\end{bmatrix}\begin{bmatrix}\alpha & 0 \\ 1 & 1\end{bmatrix} = \begin{bmatrix}\alpha^2 & 0 \\ \alpha + 1 & 1\end{bmatrix}$ Given $A^2 = B$ $\Rightarrow \begin{bmatrix}\alpha^2 & 0 \\ \alpha + 1 & 1\end{bmatrix} = \begin{bmatrix}1 & 0 \\ 5 & 1\end{bmatrix}$ Comparing: $\alpha^2 = 1 \quad \text{and} \quad \alpha + 1 = 5$ $\alpha = \pm1 \quad \text{and} \quad \alpha = 4$ Both cannot occur simultaneously $\Rightarrow$ No value possible $\boxed{\text{not possible}}$

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