concern a disk with a sector size of $512$ bytes, $2000$ tracks per surface, $50$ sectors per track, five double-sided platters, and average seek time of $10$ milliseconds.

What is the capacity of the disk, in bytes?

Given,

Sector size $=512$ bytes

Sectors per track $=50$

Tracks per surface $=2000$

Number of double-sided platters $=5$

So, number of surfaces:

$5\times 2=10$

Capacity of one track:

$512\times 50=25600$ bytes

Since,

$1K=1024$ bytes

So,

$\frac{25600}{1024}=25K$

Capacity of one surface:

$25K\times 2000=50000K$

Capacity of total disk:

$50000K\times 10=500000K$