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Let y = y(x) be the solution of the differential equation dy \over dx = 1 + xe^y - x, - √ 2 < x < √ 2 ,y(0) = 0 then, the minimum value of y(x),x \in \left( - √ 2 ,√ 2 \right) is equal to : | Watch the step-by-step video solution for this NIMCET PYQ.