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Let f(x)= \begincases -2, & -2 \le x \le 0,\\[4pt] x-2, & 0 < x \le 2, \endcases and h(x)=f(|x|)+|f(x)|. Then \displaystyle ∫_-2^2 h(x)\,dx is equal to: | Watch the step-by-step video solution for this NIMCET PYQ.