[Video Solution] Let A =
\beginbmatrix
2 & b & 1 \\
b & b^2 + 1 & b \\
1 & b & 2
\endbmatrix ... | ASPIRE STUDY
Let A =
\beginbmatrix
2 & b & 1 \\
b & b^2 + 1 & b \\
1 & b & 2
\endbmatrix where b > 0.
Then the minimum value of \dfrac\det(A)b is – | Watch the step-by-step video solution for this NIMCET PYQ.