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[Video Solution] Let A = \beginbmatrix 2 & b & 1 \\ b & b^2 + 1 & b \\ 1 & b & 2 \endbmatrix ... | ASPIRE STUDY

Let A = \beginbmatrix 2 & b & 1 \\ b & b^2 + 1 & b \\ 1 & b & 2 \endbmatrix where b > 0. Then the minimum value of \dfrac\det(A)b is – | Watch the step-by-step video solution for this NIMCET PYQ.

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