[Video Solution] If \displaystyle ∫ \tan x/1+\tan x+\tan^2x,dx = x - K/√A\tan^-1\left(K\tan x ... | ASPIRE STUDY

Name: [Video Solution] If \displaystyle ∫ \tan x/1+\tan x+\tan^2x,dx = x - K/√A\tan^-1\left(K\tan x ... | ASPIRE STUDY
Uploaded: 2026-02-15T22:52:46+00:00
Description: If \displaystyle ∫ \tan x/1+\tan x+\tan^2x,dx = x - K/√A\tan^-1\left(K\tan x + 1/√A\right) + C,\ (C\ \textis a constant of integration) then the ordered pair (K,A) is equal to : | Watch the step-by-step video solution for this NIMCET PYQ.

If \displaystyle ∫ \tan x/1+\tan x+\tan^2x,dx = x - K/√A\tan^-1\left(K\tan x + 1/√A\right) + C,\ (C\ \textis a constant of integration) then the ordered pair (K,A) is equal to : | Watch the step-by-step video solution for this NIMCET PYQ.

Published: 2026-02-15T22:52:46+00:00 Thumbnail: Open Page: https://www.aspirediary.com/library/video/15955/if-displaystyle-tan-x-1-tan-x-tan-2x-dx-x-k-a-tan-1-left-k-tan-x

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