Aspire Faculty ID #15112 · Topic: JAMIA MILLIA ISLAMIA MCA 2018 · Just now
JAMIA MILLIA ISLAMIA MCA 2018

A point equidistant from lines $4x + 3y + 10 = 0$, $5x - 12y + 26 = 0$, and $7x + 24y - 50 = 0$ is

Solution

Solving equal distance condition gives point (1,1).

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