The logic expression $(\overline{P}\land Q)\lor(P\land \overline{Q})\lor(P\land Q)$ is equivalent to

Given expression:

$(\overline{P}\land Q)\lor(P\land \overline{Q})\lor(P\land Q)$

Take common $P$ from last two terms:

$=(\overline{P}\land Q)\lor P(\overline{Q}\lor Q)$

Since,

$\overline{Q}\lor Q=1$

So,

$=(\overline{P}\land Q)\lor P$

Using identity,

$P\lor(\overline{P}\land Q)=P\lor Q$

Therefore,

$(\overline{P}\land Q)\lor(P\land \overline{Q})\lor(P\land Q)=P\lor Q$